LeetCode - Algorithms
  • Introduction
  • 1. Two Sum
  • 2. Add Two Numbers
  • 3. Longest Substring Without Repeating Characters
  • 4. Median of Two Sorted Arrays
  • 5. Longest Palindromic Substring
  • 6. ZigZag Conversion
  • 7. Reverse Integer
  • 8. String to Integer (atoi)
  • 9. Palindrome Number
  • 10. Regular Expression Matching
  • 11. Container with Most Water
  • 12. Integer to Roman
  • 13. Roman to Integer
  • 14. Longest Common Prefix
  • 15. 3Sum
  • 16. 3Sum Closest
  • 17. Letter Combinations of a Phone Number
  • 18. 4Sum
  • 19. Remove Nth Node From End of List
  • 20. Valid Parentheses
  • 21. Merge Two Sorted Lists
  • 22. Generate Parentheses
  • 23. Merge k Sorted Lists
  • 24. Swap Nodes in Pairs
  • 25. Reverse Nodes in k-Group
  • 26. Remove Duplicates from Sorted Array
  • 27. Remove Element
  • 28. Implement strStr()
  • 29. Divide Two Integers
  • 30. Substring with Concatenation of All Words
  • 31. Next Permutation
  • 32. Longest Valid Parentheses
  • 33. Search in Rotated Sorted Array
  • 34. Search for a Range
  • 35. Search Insert Position
  • 36. Valid Sudoku
  • 37. Sudoku Solver
  • 38. Count and Say
  • 39. Combination Sum
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26. Remove Duplicates from Sorted Array

Problem

Given a sorted array, remove the duplicates in-place such that each element appear only once and return the new length.

Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.

Example:

Given nums = [1,1,2],

Your function should return length = 2, with the first two elements of nums being 1 and 2 respectively.
It doesn't matter what you leave beyond the new length.

Related Topics:

Array Two Pointers

Analysis

设置两个指标,一前一后:

  • 当重复时,前动,后不动。

  • 不重复时,前后都动,并且更新后指标的值。

Code

class Solution {

    fun removeDuplicates(nums: IntArray): Int {

        var ri = 0
        for (i in 1 until nums.size) {
            if (nums[ri] != nums[i]) {
                ri++
                nums[ri] = nums[i]
            }
        }

        return ri + 1
    }
}
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Last updated 6 years ago