# 35. Search Insert Position

## Problem

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

**Example 1:**

```
Input: [1,3,5,6], 5
Output: 2
```

**Example 2:**

```
Input: [1,3,5,6], 2
Output: 1
```

**Example 3:**

```
Input: [1,3,5,6], 7
Output: 4
```

**Example 4:**

```
Input: [1,3,5,6], 0
Output: 0
```

**Related Topics:**

`Array` `Binary Search`

## Analysis

二分查找确定插入点。

## Code

```kotlin
class Solution {

    fun searchInsert(nums: IntArray, target: Int): Int {

        var left = 0
        var right = nums.lastIndex
        var mid: Int

        while (left <= right) {

            mid = (left + right) / 2
            when {
                nums[mid] == target -> return mid
                nums[mid] < target -> left = mid + 1
                else -> right = mid - 1
            }
        }

        return left
    }
}
```
